There is a solution to 97 exercise problems in 11th mathThe chapter in 11th standard is important.If a student wants to get good marks they must master this chapter.Derivative concepts are the focus of the chapter as well as the tools that are developed based on the derivatives that are applied in real life.If an instance happens over some time the average of the rate is x.

Then the averate rate will be the same.A student wants to score 90 percent agreegate in all subjects.He/she needs to score higher in some subjects than others as he/she could score lower in other subjects.The time rate of change of score is calculated from the total score till now and the number of subjects.Any moving object is also applicable.

A runner is running at a high rate of speed.The distance travelled is the measure of the rate of speed.The speed will be 3/6*60 if the runner is at 3 km from the start.It's equal to 30 km/h.This is only a partial measure of rate.

The rate of speed will go up toIt's the same as 60 km/HR.The following four problems are solved in calculus.In the future we will see the first two details.In a circle the tangent to the circle will cross the border of the circle which will be the same as the radius that goes through it.

There are cases where a curve only goes through the border once.There are occurances where the curve might have multiple points.It's easy to find the slope of the line that goes through two points in a curve.Differential quotient is used to find the curve's slope.It is divided into two parts delta y and Delta x.

The slope of the curve is similar to the slope of the tangent line.The position function has to be used to calculate the velocity.This is simplified by dividing the change in distance by the change in time.It would be simpler to calculate the velocity using the position function if we could measure the time and distance at two point in time.The function of x is always a function of differentiation.

Y will be differentiated with respect to x.This will be a result of it.We will get f'(x) if we differentiate f(x)( x)(xThe dy/x can be written as y'.Let's look at a few examples of differentiating y with x.

10 x9 will result from x 10 differentiating.The difference between 20 x19 and x20 is called a differentiating willlut.-3 x-4 will be the result of x-2 differentiating.Differentiating x-11 will cause the same thing to happen.Leaving x1/2 the same will result in 1/2x1/2.

If y is 10 x9 + 7 x6 + 5 x4 + 3 x2 then dy/dx will be 10 x9 + 7 x6 + 5 x4 + 3 x2We will have zero if we differentiate a constant.Any element with no x is considered constant.When we differentiate we get six*0*x-1 which will result in zero.The result will be 3 x2 and 0 x3