There is a solution to 97 exercise problems in the 11th class.There is a chapter in 11th standard that is very important.mastering this chapter is necessary for a student to score good marks.Derivative concepts are the focus of the chapter and the tools that are developed based on the derivatives that are applied in real life are also given special focus.When we know the average of the rate over time it's x.

The averate will stay the same.The student wants to score 90 percent on all subjects.He/she has to score higher in some subjects than others as he/she might score less in other subjects.The average rate of score is the time rate of change of score which is defined by the number of subjects and total score.The same can be applied to any object that is moving.

A runner is at a speed of 20km/hr.The measure of the rate of speed is the distance travelled divided by the time.If the runner is at 3 km from the beginning of the run the speed will be 3/6*60.This is the same as 30 km per hour.This is not a true depiction of the rate.

The speed at which it will be will be (5-3)/(8-6).60 km/hr is the same.The following four major problems are solved by mathematiciansIn the future we will see the first two in detail.For a circle the tangent to a circle will cross the border of the circle which will be the same as the radius that goes through that point.

There are situations in which the curve only passes once through the border.There are other occurances where the tangent might travel through multiple points in the curve.The easiest way to calculate the tangent of a curve is to find the slope of the line that passes through the two points in that curve.If you want to find the slope of the curve differential quotient is used.It is divided into two parts Delta y and Delta x.

The slope of the curve isalso known as the slope of the tangent line.The position function is used for calculating thevelocity.The ration of change in distance divided by time would be simplified.The position function is simpler to use when we measure the time and distance at two points in time.The function of x is always the basis of the logic of differentiation.

With respect to x we will distinguish y.This will cause dy/dy.We will get f'(x) if we differentiate f( x)(x)(xThe writing of dy/dx can be written as y'.There are a few examples of differentiating y from x.

10 x 9 will result from the x10 differentiating.There are 20 x 19 differentiating willlut.-2 x-4 is what the differentiating will result in.Differentiating x-11 will make the difference.A differentiation of x1/2 will result in 1/2x1/2.

When we differentiate y with respect to x we will get dy/dx of 10 x9 + 7 x6 + 5 x4We'll get nothing if we differentiate a constant.Constant is the name for any element without x.We get 6*0*x-1 which results in zero.The result is 0 x3 and 3 x2