You can find the solution to 97 Exercise Problems in 11th math here.This is a chapter in the 11th standard.This chapter needs to be mastered if a student wants to get good marks.The chapter focuses on derivative concepts and other related concepts as well as the tools that are developed based on the derivatives that are applied in real life.The average rate is x if the instance happens over time.

As x will remain the averate rate.For example a student wants to score at least 90% on all subjects.He/she has to score higher in some subjects as he/ she might score lower in other subjects.The time rate of change of score is defined by total score till now and the number of subjects.Any moving object is the same as always.

A runner can run at a speed of 20 km/hour.At any point in time the measure of rate of speed is the distance travelled divided by the time.If a runner is at 3 km from the start of the run the speed would be 3/6*60.This is the amount of time it takes to travel 30 km/hr.This isn't the true measure of rate.

The rate of speed will go up toIt is equal to 60 kilometres per hour.The following four major problems are solved in calculus by mathematicians.There will be more details in the coming section.For a circle the tangent to the circle will cross the border of the circle which will be the same as the radius that goes through it.

There are instances where a curve only passes once through the border of the curve.In the curve there are other occurances where the tangent could pass through multiple points.The easiest way to find the slope of the line that goes through two points in a curve is to find it.The slope of the curve can be found with differential quotient.It is divided into two parts: Delta y andDelta x.

The slope of the curve is also known as the line's slope.The function that is used to calculate the velocity is position function.It would be simpler by dividing the change in distance by time.It would be easier to calculate the velocity using the position function when we measure the time and distance at two points in time.The logic of differentiation states that y is a function of x.

We're going to distinguish y with respect to x.This will add up to dy/dx.We will get f'(x) if we differentiate f(x)(x(xIt's possible to write dy/x as y'.Let us look at some examples of differentiating y with x.

10 x9 is the difference between x10 and x10.In 20 x19 the differentiating willlut will be x20.x-2 will result in -2 x-4.Differentiating x-11 will cause the same behavior in -11x-12.x1/2 will be differentiated into 1/2x1/2.

If y is x10 + x7 + x5 + x3 then dy/dx is 10 x9 + 7 x6 + 5 x4 + 3 x2.Zero will be gotten if we differentiate a constant.Any element that is not x is considered to be constant.We get 6*0*x-1 which will result in zero when we differentiate.Zero + 3 x2 will be the result of differentiating 5 + x3