The answer to 97 exercise problems in 11th math is here.This chapter is critical in the 11th standard.This chapter is needed for a student to get good marks.Special focus is given to the tools that are developed based on the derivatives that are applied in real life as well as the chapter that focuses on derivative concepts.If the instance happens over a period of time and the average of the rate is x that's when we know it's happening.

The averate rate will be kept as x.For example if a student wants to get an agreegate score of 90 percent on all subjects.He/she has to score higher in some subjects than in others as he/she might score lower in other subjects.The rate of change of score is defined by the total score and the number of subjects.The same applies when moving an object.

A runner is running at a speed of 20km/hrs.The rate of speed is the distance travelled divided by the time takenAt 6 minutes if the runner is at 3 km from the start the speed would be 3/6*60.30 km/h is equal to this.This is not a real measure.

The rate of speed will go up to COUNTER60 miles per hour is equal to this.Four major problems are solved in Calculus.In thecoming section we will see the first two details.For a circle the tangent to the circle will cross the border of the circle which will correspond to the radius that goes through it.

There are scenarios where a curve only passes one time through the border.There are other occurances where the curve can be multiple points in length.The easiest way to find the slope of the line that passes through two points is to use the curve as a reference.The slope of the curve is determined with a differential quotient.It is divided into two parts one being Delta y and the other Delta x.

The curve's slope is called the slope of the curve.Thevelocity is calculated using a position functionThis would be simplified with a ration of the change in distance divided by time.It would be simpler to calculate the velocity using the position function if we measured the time and distance at a point in time.It is always a function of x that y is differentiation.

We will differentiate with respect to x.This result will be dy/dx.We'll get f'(x) if we differentiate f( x)(x)(The same can be said of dy/dx.We will see a few examples of differentiating y with x.

10 x9 is the result of x10 distinguishing.The willlut in x20 is different than in x19.-2 x-4 will result from x 3 differentiating.-11x-12 will be differentiating x-11.Equalizing x1/2 will result in equalizing 1/2x1/2.

If y is defined as x10 + x7 + x5 + x3 we will get dy/dx of 10 x9 + 7 x6 + 5 x4 + 3 x2.A zero will be given if we differentiate a constant.There is no element that is not constant.When we differentiate we get 6*0*x-1 and that will result in zero.A difference between 5 + x3 will result in 0 and 3 x2.