Here is the solution to 97 Exercise Problems in 11th maths for Tamilnadu.This is a major chapter in the 11th standard.The chapter is important for a student to get good marks.The tools that are developed based on the derivatives that are applied in real life are given special focus in the chapter.When we know the average rate is x the instance can happen over time.

Only the averate rate will remain as it is.A student wants to score 90 percent agreegate of all subjects.He/she needs to score higher in some subjects than others as he/she could score lower in other subjects.The time rate of change of score is defined by the total score till now and the number of subjectsAny moving object is also subject to the same rules.

A runner is running at a high speed.The rate of speed is the difference between the distance traveled and the time taken.If the runner is at 3 km from the start of the run the speed will be 3/6*60.30 kilometer/hr is equal to this.The true measure of rate is not this.

The rate of speed will go up to-It is equal to 60 km/hrs.The following are some of the major problems that mathematicians solve in calculus.In the next section we'll see the first two in detail.The tangent of the circle to the border of the circle will be the same as the radius of the circle.

There are some scenarios in which a curve only passes through the border once.There are other occurances where the tangent may go through multiple points in the curve.The easiest way to calculate the tangent of a curve is to find the slope of the line that crosses two points in that curve.It is possible to find the slope of the curve using the differential quotient.It is divided into two groups: Delta y and Delta x.

The slope of the curve is what's known as the slope of the curve.The velocity is calculated from a position function.This would be simplified by dividing change in distance by time.If we measure the time and distance at two points in time it would be simpler to calculate the velocity using the position function.Y is always a function of x that's the logic of differentiating.

We will differentiate y and x with that.The result of this will be dy.We will get f'(x) if we differentiate f)(Y' can be written as dy/dx.Let's see a few examples of differentiating x and y.

10 x9 is the difference between x10 and x10The willlut in 20 x19 is called x20.-2 x-4 will result from x-3) differentiating.The difference between x-11 and x-12 will be different.Differentiating x1/2 will result in 1/2x-1.

When we differentiate y with respect to x we will get dy/dx which is 10 x9 + 7 x6 + 5 x4 + 2 x2zero will be obtained if we differentiate a constant.It is called as constant if there is no x.6x0 when we differentiate we get 6*0*x-1 which will be zero.The result will be 0 plus 3 x2.