Here is the solution to 97 Exercise Problems in 11th maths.This is a very important part of 11th standard.This chapter is necessary for a student to get good marks.Special focus is given to derivative concepts and other related ones as well as the tools that are developed based on the derivatives that are applied in real life.If the instance happens over a period of time then the average rate is x.

The averate rate will remain at x.A student wants to get a perfect agreegate score of all subjects.He/she needs to score higher in some subjects as he/she may score lower in other subjects.The average rate of score is the time rate of change of score which is defined by the total score till nowIt's the same for moving objects.

A runner at a speed of 20 km/hr can be considered.The distance travelled divided by the time taken is the measure of the rate of speed.At 6 minutes the speed is 3/6*60 if the runner is at 3 km from the start of the run.It's the same as 30km/HR.This is not a true indicator of rate.

The current speed is 5-3)/(8-6)*60It is equal to 60 km/HR.There are four major problems that mathematicians solve in calculus.In the coming section we will be seeing the first two.For a circle the tangent to the circle will cross the border of the circle which will be the same as the radius that goes through it.

There are situations where the curve only passes through the border once.There are other occurances in the curve where the tangent might pass through multiple points.The easiest way to find the slope of the line is to find two points in the curve.The slope of the curve is determined with differential quotient.It is divided into two parts: Delta x and Delta y.

The slope of a curve is known as the slope of the curve.The position function is used to calculate the velocityIt would be simplified by dividing the change in distance by the time.It would be simpler to use the position function if we measured the time and distance at two points in time.Y is a function of x that's the logic of differentiation.

We will differentiate them with respect to x.This will result in a result.We will get f'(x) if we differentiate f(X)(x)(xThe dy can be written as y'.Let's see examples of differentiating y and x.

10 x9 will be the result of X10 differentiating.The willlut in x20 is different from the willlut in x19The result is x-4.Differentiating x-11 will cause the same thing in -11x-12.The result of differentiating x1/2 will be 1/2x1/2.

When we differentiate y with respect to x we will get dy/dx which is 10 x9 + 7 x6 + 5 x4 + 3 x2We will get zero for differentiating a constant.Any element that does not have x is a constant.We get 6x0 when we differentiate and it will result in zero.The result is 0 + 3 x2 if differentiating 5 + x3