You can find the solution to 97 exercise problems in 11th math.This chapter is very important.If a student wants to get good marks then mastering this chapter is important.Derivative concepts and other related concepts are the focus of the chapter and the tools that are developed based on the derivatives that are applied in real life are also given a special focus.If the instance happens over a long time the average of the rate is x.

The averate will stay as x.A student wants to get a score of 90 percent on all subjects.He/she needs to score higher than 90 in some subjects as he/she may score lower than 90 in other subjects.The average rate of score is the time rate of change of score which is defined by total score till now.It is the same for any moving object.

A person is running at a speed of 20 km/hr.The distance traveled is divided by the time taken to calculate the rate of speed.The speed would be 3/6*60 if the runner was at 3 km from the start of the run.It's the same as 30 km/HR.This is only a measure of rate.

The rate of speed will go from 5 to 8 in 60 seconds.60 km/HR is equal.The following four major problems are solved in calculus.In the next section we'll see the first two details.The circle's border will be crossed by the tangent to the circle and the radius that goes through that point.

Sometimes a curve only goes through the border of the curve once.There are other occurances where the curve can be multiple points.The easiest way to calculate the tangent of a curve is to find the slope of the line that goes through two points in the curve.The slope of the curve can be found using the differential quotient.It is divided into two parts delta y and x.

The slope of the curve is the same as the slope of the tangent line.The velocities are calculated using the position function.This could be simplified by dividing the change in distance by the change in time.It would be simpler to use the position function when we measure the time and distance at two points in time.The logic says y is always a function of x.

With respect to x we'll differentiate y.This result will be dy.We will get f'(x) if we differentiate f(X)(x)(xSimilarly y' can be written as dy.Let us look at some examples of differentiating y and x.

The difference between x10 and x9 will be 10 x9.In 20 x19 there are differentiating willlut.It will result in -2 x-4.-11x-12 is differentiated by differentiating x-11.1/2x-1/2 is the result of differing x1/2.

When we differentiate y with respect to x we'll get a dy/dx of 10 x9 + 7 x6 + 5 x4 + 3 x2We will not get anything if we differentiate a constant.Any element that doesn't have x is always constant.We get 6*0*x-1 which will result in zero when we differentiate.It will result in 0 and 3 x2.