Here is the solution to 97 exercise problems in 11th math.In 11th standard this is a very important chapter.This chapter is important if a student wants to get good marks.The chapter focuses on derivative concepts and other related concepts as well as the tools that are developed based on the derivatives that are applied in real life.If the instance occurs over a period of time the average of the rate is x.

The averate rate will not be changed.A student wants to get a score of 90% on all subjects.He/she needs to score higher than 85% in some subjects as he/she might score less than 85% in other subjects.The average rate of score is the time rate of change of score which is defined by the total score and the number of subjects.The same applies to any object that moves.

A runner running at a speed of 20 km/hr is considered.The distance travelled divided by the time taken is the rate of speed.If the runner is at 3 km from the start the speed would be 3/6*60.This is the same as 30 km/h.This isn't a true measurement of rate.

The current speed is not known.It's the same as 60 km/hr.The following four major problems are solved in calculus.In the coming section we will be seeing first two details.The circle's border will be crossed by the tangent to the circle to the point that goes through it.

Sometimes a curve can only pass through the border of the curve once.There are other occurances where the curve might go through multiple points.The easiest way to calculate the tangent of a curve is to find the slope of the line that goes through the two points in the curve.For finding the slope of the curve differential quotient is used.It is divided into two parts delta y anddelta x.

The curve's slope is also known as the slope of the line.The function that calculates the velocity is position function.It would be simplified by dividing the change in distance by time.It would be simpler to calculate the velocity using the position function if we measure the time and distance at two points in time.The logic of differentiation says that y is a function of x.

We'll differentiate y with respect to x now.This will result in a number.We will get f'(x) if we differentiate f(x)(X)(xThe word dy can be written as Y'.There are few examples of differentiating y with x.

10 x9 is what will result from x10 differentiating.The willlut in x20 is different to the willlut in x19.x-3 will result in x-4.Differentiating x-11 will cause it to relut in -11x-12.1/2x-1/2 will be the result of differentiating x1/2.

When we differentiate y with respect to x we will get a dy/dx of 10 x9 + 7 x6 + 5 x4 + 3 x2.We will get zero if we separate a constant.Any element that isn't x is constant.When we differentiate 6*0*x-1 will result in zero.The result is 0 and 3 x2.